CAIE Past Paper Searcher · CAIE A-Level 物理/化学/进阶数学 4卷真题更新到25冬季卷。需要帮助联系:admin@wwww.us.kg

9231_s23_qp_21

科目:进阶数学 Further Mathematics (9231)

年份:2023 夏季

试卷:Paper 21

总页数:14

章节:9231 Further Mathematics

← 返回全部文件列表


Page 2

BLANK PAGE

Page 3

1. (a) Show that the system of equations
$$x + 2y + 3z = 1,$$
$$4x + 5y + 6z = 1,$$
$$7x + 8y + 9z = 1,$$

does not have a unique solution. [2]

(b) Show that the system of equations in part (a) is consistent. Interpret this situation geometrically. [3]

Page 4

2 Use the substitution $z = x + y$ to find the solution of the differential equation

$$\frac{dy}{dx} = \frac{1 + 3x + 3y}{3x + 3y - 1}$$

for which $y = 0$ when $x = 1$. Give your answer in the form $a \ln(x+y) + b(x-y) + c = 0$, where $a, b$ and $c$ are constants to be determined. [7]

Page 5

3 (a) By considering the binomial expansion of $(z + z^{-1})^4$, where $z = \cos \theta + i \sin \theta$, use de Moivre's theorem to show that $\cos^4 \theta = \frac{1}{8}(\cos 4\theta + 4\cos 2\theta + 3)$. [5]

(b) Use the substitution $x = \sin \theta$ to find the exact value of $\int_0^{\frac{\pi}{2}} (1 - x^2)^{\frac{3}{2}} dx$. [3]

Page 6

4 The integral $I_n$ is defined by $I_n = \int_0^1 (1+x^5)^n \, dx$.

(a) By considering $\frac{d}{dx}\left(x(1+x^5)^n\right)$, or otherwise, show that

$(5n+1)I_n = 2^n + 5nI_{n-1}$. [5]

Page 7

(b) Find the exact value of $I_3$. [4]

Page 8

5 The matrix $A$ is given by

$$A = \begin{pmatrix} 18 & 5 & -11 \\ 8 & 6 & -4 \\ 32 & 10 & -20 \end{pmatrix}.$$

(a) Show that the characteristic equation of $A$ is $\lambda^3 - 4\lambda^2 - 20\lambda + 48 = 0$ and hence find the eigenvalues of $A$. [4]

Page 9

(b) Find a matrix $P$ and a diagonal matrix $D$ such that $A^5 = PDP^{-1}$. [6]

Page 10

6 Find the particular solution of the differential equation

$$\frac{d^2x}{dt^2} - 12 \frac{dx}{dt} + 36x = 37 \sin t,$$

given that, when $t = 0$, $x = \frac{dx}{dt} = 0$. [11]

Page 11

11

© UCLES 2023 9231/21/M/J/23 [Turn over]

Page 12

7 (a) Use the substitution $u = x^2 - 1$ to find $\int \frac{x}{\sqrt{x^2 - 1}} dx$.

The diagram shows the curve with equation $y = \cosh^{-1}x$ together with a set of $(N-1)$ rectangles of unit width.

(b) By considering the sum of the areas of these rectangles, show that

$$\sum_{r=2}^{N} \ln(r + \sqrt{r^2 - 1}) > N \ln(N + \sqrt{N^2 - 1}) - \sqrt{N^2 - 1}$$

Page 13

(c) Use a similar method to find, in terms of $N$, an upper bound for $\sum_{r=2}^{N} \ln\left(r + \sqrt{r^2 - 1}\right)$. [3]

Page 14

8 (a) Starting from the definitions of sech and tanh in terms of exponentials, prove that

$$1 - \text{sech}^2 t = \tanh^2 t.$$  

[3]

The curve $C$ has parametric equations

$$x = \frac{1}{2} \tanh^2 t + \ln \text{sech} t, \quad y = 1 + \tanh^4 t, \quad \text{for } t > 0.$$  

(b) Show that $\frac{dy}{dx} = -4 \text{sech}^2 t.$  

[5]

Page 15

(c) Find the coordinates of the point on $C$ with $\frac{d^2y}{dx^2} = -\frac{9}{2}$, giving your answer in the form $(a + \ln b, c)$ where $a, b$ and $c$ are rational numbers. [6]